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In a round‐robin tournament, after each team has played exactly four matches, the number of wins/ losses of 6 participating teams are as follows
Question

In a round‐robin tournament, after each team has played exactly four matches, the number of wins/ losses of 6 participating teams are as follows

Which of the two teams have certainly NOT played with each other?

A.

A and B

B.

C and F

C.

E and D

D.

B and E

Correct option is D


Given:
1. It’s a round-robin tournament with each team playing exactly four matches.
2. There are 6 teams (A, B, C, D, E, F) with the following win/loss records:
· Team A: 4 wins, 0 losses
· Team B: 0 wins, 4 losses
· Team C: 3 wins, 1 loss
· Team D: 2 wins, 2 losses
· Team E: 0 wins, 4 losses
· Team F: 3 wins, 1 loss
Observations:
1. Team A has 4 wins and 0 losses, which means Team A won all of its matches.
2. Team B and Team E both have 0 wins and 4 losses, which means they lost all of their matches.
3. Since each team plays exactly four matches, any team with 0 wins could not have played against any other team with 0 wins (because they would each need to lose that match, which is impossible in a single game).
Conclusion:
Since Team B and Team E both lost all of their matches, it’s certain that B and E did not play against each other. If they had, one of them would have at least one win.
Answer:
The correct answer is: (d) B and E

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