In a group of zebras and ducks, the number of legs is 48 more than twice the number of heads. The number of zebras is

Correct option is C

Given:

A group consists of zebras and ducks.

Let the number of zebras be z, and the number of ducks be d.

Each animal has one head, so the total number of heads is z + d.

Zebras have 4 legs each, and ducks have 2 legs each, so the total number of legs is: 4z + 2d.

The total number of legs is 48 more than twice the total number of heads:

4z + 2d = 2(z + d) + 48

Formula Used:

1. Total heads:

Heads = z + d

2. Total legs:

Legs = 4z + 2d

3. Relationship between legs and heads:

4z + 2d = 2(z + d) + 48

Solution:

1. Start with the equation:

4z + 2d = 2(z + d) + 48

2. Simplify:

4z + 2d = 2z + 2d + 48

3. Subtract 2z + 2d from both sides:

2z = 48

4. Solve for z:

z = 24

Thus, the number of zebras is 24.

Final Answer:

The number of zebras is 24.