In a consignment of electric bulbs, 4% were broken and from the remainder, 25% were found to be defective. If the total number of broken and defective bulbs is 112, then find the number of bulbs in the consignment.

Correct option is C

​Given:

4% are broken, and from the remaining 96%, 25% are defective.

Total broken and defective bulbs = 112.

Solution:

Let the total number of bulbs be x

Broken bulbs = 4% of x = 0.04x

Remaining bulbs after broken = 96% of x = 0.96x

Defective bulbs = 25% of 0.96x =$$0.25 \times 0.96x = 0.24x.$$​​

Total broken and defective bulbs:

​$$0.04x + 0.24x = 112 \implies 0.28x = 112$$​​

​$$x = \frac{112}{0.28} = 400$$​​