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    In a common base transistor configuration. If IB=0.11 mA and IE=1.25 mA, then IC is:
    Question

    In a common base transistor configuration. If IB=0.11 mA and IE=1.25 mA, then IC is:

    A.

    -1.08 mA

    B.

    -1.36 mA

    C.

    1.06 mA

    D.

    1.14 mA

    Correct option is D

    In a common base transistor configuration, the collector current IC can be calculated using:IE=IC+IBGiven IB=0.11 mA and IE=1.25 mAIC=IEIB=1.25 mA0.11 mA=1.14 mA\text{In a common base transistor configuration, the collector current } I_C \text{ can be calculated using:} \\I_E = I_C + I_B \\\text{Given } I_B = 0.11 \text{ mA and } I_E = 1.25 \text{ mA} \\I_C = I_E - I_B = 1.25 \text{ mA} - 0.11 \text{ mA} = 1.14 \text{ mA}​​

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