In a class of 50 students, 18 take Computer, 26 take Sanskrit and 2 take Computer and Sanskrit. How many students in the class are not enrolled in either Sanskrit or Computer ?

Correct option is D

Given:

• Total students = 50
• Students taking Computer = 18
• Students taking Sanskrit = 26
• Students taking both Computer and Sanskrit = 2

Step 1: Find students taking either Computer or Sanskrit.

The formula for students in either group is:

$$\text{Students in Computer or Sanskrit}=(\text{Students in Computer})+(\text{Students in Sanskrit})-(\text{Students in both})$$

Substitute the values:

$$\text{Students in Computer or Sanskrit}=18+26-2=42$$

Step 2: Find students not enrolled in either subject.

The total number of students is 50, so the number of students not enrolled in either subject is:

$$\text{Students not in Computer or Sanskrit}=\text{Total students}-\text{Students in Computer or Sanskrit}$$

Substitute the values:

$$\text{Students not in Computer or Sanskrit}=50-42=8$$

Final Answer: D. 8