Correct option is C

M(13) → 1 + 3 = 4
O(15) → 1 + 5 = 6
B(2) → 2
I(9) → 9
L(12) → 1 + 2 = 3
I(9) → 9
T(20) → 2 + 0 = 2
Y(25) → 2 + 5 = 7
X(24) → 2 + 4 = 6
A(1) → 1
M(13) → 1 + 3 = 4
I(9) → 9
N(14) → 1 + 4 = 5
A(1) → 1
T(20) → 2 + 0 = 2
I(9) → 9
O(15) → 1 + 5 = 6
N(14) → 1 + 4 = 5