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If y = 26, then what is the value of ​yy3−y2y\sqrt {y^3-y^2}yy3−y2​ ?​
Question

If y = 26, then what is the value of

yy3y2y\sqrt {y^3-y^2} ?​

A.

3280

B.

3380

C.

3580

D.

3480

Correct option is B

Given:

If y = 26

yy3y2y\sqrt {y^3-y^2}​​
Solution:

Substituting y=26:

y2y1=262261y^2 \sqrt{y - 1} = 26^2 \sqrt{26 - 1}​​

= 67625676 \sqrt{25}​​

=676×5= 3380

Option (B) is right.

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