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    If x,y and z are numbers between 1 and 10 , then 4x+6y+9z+2 is
    Question

    If x,y and z are numbers between 1 and 10 , then 4x+6y+9z+2 is


    A.

    odd


    B.

    even


    C.

    even if is even


    D.

    odd if is odd

    Correct option is D

    We are given the expression:

    4x+6y+9z+2

    where x,y and z are numbers between 1 and 10.

    Step 1: Identify the Parity of Each Term

    • 4x is always even (since 4 is even, multiplying by any integer keeps it even).

    • 6y is always even (since 6 is even).

    • 9z depends on z:

      • If z is even, 9z is even.

      • If z is odd, 9z is odd.

    • The constant +2 is even.

    Step 2: Find When the Sum is Odd or Even

    • The sum 4x+6y+9z+2 is a sum of even + even + 9z + even.

    • Since even + even + even = even, and even + odd = odd, the only factor that changes the parity is 9z.

    • If z is even → 9z is even → Whole sum is even.

    • If z is odd → 9z is odd → Whole sum is odd.

    Since the expression is odd if z is odd, the correct answer is:

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