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If x = 25 and y = 13 then find: ​(x2−2xy+y2)\sqrt{(x²-2xy + y²)}(x2−2xy+y2)​​​
Question

If x = 25 and y = 13 then find:
(x22xy+y2)\sqrt{(x²-2xy + y²)}​​

A.

12

B.

38

C.

13

D.

10

Correct option is A

Given:

x = 25 , y= 13 

Formula Used:

x2+y2+2xy=(xy)2x^2 + y^2 +2xy = (x-y)^2​​


Solution:

(x22xy+y2)\sqrt{(x²-2xy + y²)}  

(xy)2\sqrt{(x- y)^2}   

(2513)2\sqrt{(25- 13)^2}  

(12)2\sqrt{(12)^2}  

= 12

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