If , where and are integers, then the value of is:

Correct option is C

Trial x = 1
Substitute x = 1 into the equation:
12 + y2 − 1y − 3y + 3 = 0,
12 + y2 - 1y - 3y + 3 = 0,
y2 − 4y + 4 = 0.
This factors as:
(y−2)2 = 0
Thus, y = 2
Verify and compute 2x+3y
For x = 1 and y = 2, substitute back:
2x + 3y = 2(1) + 3(2) = 2+6 = 8