If the surface area of a spherical ball is 616 m². Its volume is:

Correct option is A

Given:

Surface area of a spherical ball is 616 m².

Formula used:

Surface Area of Sphere = $$S = 4\pi r^2$$

Volume of Sphere = $$V = \frac{4}{3} \pi r^3$$

Solution:

​$$S = 4\pi r^2$$​​

​$$616 = 4\pi r^2$$= $$r^2 = \frac{616}{4\pi} = \frac{616}{12.56} = 49 \, \text{m}^2$$

=> $$r$$= 7$$m$$ 

So, Volume; 

​$$V = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (7)^3 = \frac{4}{3} \pi (343)$$

$$V = \frac{4}{3} \times 3.14 \times 343 = \frac{4}{3} \times 3.14 \times 343 \approx 1437.333 \, \text{m}^3$$

Thus the correct answer is (A)
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