If the perimeter of a rhombus is 200 cm and one of its diagonal is 80 cm, then what is the area of the rhombus?

Correct option is A

Given:
Perimeter of the rhombus = 200 cm
One diagonal (d₁) = 80 cm
Formula Used:
Side of the rhombus =  $$\frac{\text{Perimeter}}{4}$$​​
Area of the rhombus =  $$\frac{1}{2} \times d_1 \times d_2$$​​
Solution:
​$$\text{Side} = \frac{200}{4} = 50 \, \text{cm}$$​​

​$$d_2 = \sqrt{4 \times \text{Side}^2 - d_1^2}\\d_2 = \sqrt{4 \times 50^2 - 80^2} = \sqrt{10000 - 6400} = \sqrt{3600} = 60 \, \text{cm}$$​​
 Area of the rhombus =$$\text{Area} = \frac{1}{2} \times 80 \times 60 = 2400 \, \text{cm}^2$$​​
Thus, the area of the rhombus is 2400 cm².