Find the perimeter of a rhombus whose diagonals are of lengths 6 cm and 8 cm.

Correct option is C

Given:

Length of the first diagonal d1= 6 cm

Length of the second diagonal d2 = 8 cm

Formula Used:

The length of each side of the rhombus ss is given by:

s = $$\sqrt{\left( \frac{d_1}{2} \right)^2 + \left( \frac{d_2}{2} \right)^2}$$​​

The perimeter of the rhombus is given by: Perimeter = 4s

Solution:

Side = $$\sqrt{\left( \frac{6}{2} \right)^2 + \left( \frac{8}{2} \right)^2}$$​​

Side = $$\sqrt{\left( 3 \right)^2 + \left( 4 \right)^2}$$​​

Side = $$\sqrt{ 9 + 16}$$​​

Side = $$\sqrt{25}$$​​

Side = 5 cm

The perimeter of the rhombus is:

Perimeter = 4 × 5 = 20 cm

Thus, the perimeter of the rhombus is 20 cm.