If the numerator of a fraction is increased by 10% and its denominator is diminished by 10%, then the fraction becomes 11/45. Find the original fraction.

Correct option is B

Given:

Let the original fraction be$$\frac{n}{d}$$​, where 'n' is the numerator and 'd' is the denominator.

Solution:
The new fraction after the changes is given by:
​$$\frac{n + 10\% \times n}{d - 10\% \times d} = \frac{11}{45}$$​​

then, equation for the new fraction:
​$$\frac{1.1n}{0.9d} = \frac{11}{45}\\\ \\\frac{n}{d} = \frac{11}{45} \times \frac{0.9}{1.1} \\\ \\\frac{n}{d} = \frac{1}{5}$$​​
The original fraction is$$\frac{1}{5}$$​.