If the inner radius of a hemispherical bowl is 5 cm and its thickness is 0.25 cm, then find the volume of the material required in making the bowl. (use π=22/7) (Rounded up to two places of decimals).

Inner radius of the hemispherical bowl $$r_1 = 5 \text{cm}$$​

Thickness of the bowl $$t = 0.25 \text{cm}$$​.

Outer radius of the bowl $$r_2 = r_1 + t = 5 + 0.25 = 5.25\text{cm}$$​

​$$\pi = \frac{22}{7}$$​​

Volume of a hemisphere =$$\frac{2}{3} \pi r^3.$$​

Volume of material required = Volume of the outer hemisphere – Volume of the inner hemisphere.