If the income of Richa is $$9 \frac{1}{11}$$% more than that of Meena, then the income of Meena is less than that of Richa by:​

Correct option is D

Given:

the income of Richa is $$9\frac{1}{11}$$% more than that of Meena, then the income of Meena is less than that of Richa by:

Solution:

​$$9\frac{1}{11}$$%  = $$\frac{1}{11}$$​​

Let the income of  Meena is 11 then the income of Richa is 12  (1 more then Meena )

Now  income of Meena is 1 less than Richa 

So, income of Meena is $$\frac{1}{12}$$ of income of Richa

$$\frac{1}{12}$$ = $$\frac{1}{12}$$ × 100 %  =  $$8\frac{4}{12}$$ %

So, the income of Meena is $$8\frac{4}{12}$$ % less than that of Richa ​