If the income of Richa is $$9 \frac{1}{11}$$% more than that of Meena, then the income of Meena is less than that of Richa by:

Correct option is D

If the income of Richa is $$9 \frac{1}{11}$$​% more than that of Meena, then the income of Meena is less than that of Richa by:

Solution: 

 $$9 \frac{1}{11}$$% = $$\frac{100}{11} \% = \frac{1}{11}$$​

Let the income of Meena = 11 unit 

then the Income of Richa = 11 + 1 = 12 unit

Then  = $$\frac{(12-11)}{12}\times100\% \\\ \\ =8 \frac{1}{3}\%$$  

Meena income is $$8\frac{1}{3}\%$$  less than the Richa income.