Correct option is A
Solution:
Let the two numbers are 8a and 8b.
LCM (8a, 8b) = LCM 8(a, b) = 160
Put a = 4 and b = 5,(where a and b both should be a single digit.)
LCM = 8 ×4×5 = 160
sum of the numbers = 8 (4 + 5) = 72
Solution:
Let the two numbers are 8a and 8b.
LCM (8a, 8b) = LCM 8(a, b) = 160
Put a = 4 and b = 5,(where a and b both should be a single digit.)
LCM = 8 ×4×5 = 160
sum of the numbers = 8 (4 + 5) = 72
Find the smallest number which when increased by 20 is completely divisible by 12, 20, 15, 18 and 24.
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Three bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ring simultaneously at 8:00 am. They will ring simultaneously again at
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The HCF and the LCM of two numbers are 4 and 2600, respectively. If one of the numbers is 104, find the other one.
Suggested Test Series
Suggested Test Series