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    If the first number and the second number is 25% and 50% more than the third number respectively, find the respective ratio between the first and t
    Question

    If the first number and the second number is 25% and 50% more than the third number
    respectively, find the respective ratio between the first and the second number.

    A.

    1 : 2

    B.

    5 : 6

    C.

    6 : 5

    D.

    2 : 1

    Correct option is B

    Given:

    Let the third number be 'x'.

    Solution:
    The first number is 25% more than the third number:
    First number = x+25%×x=x+25100×x=5x4x + 25\% \times x = x + \frac{25}{100} \times x = \frac{5x}{4}​​
    The second number is 50% more than the third number:
    Second number = x+50%×x=x+50100×x=3x2x + 50\% \times x = x + \frac{50}{100} \times x = \frac{3x}{2}​​

    We have the first number as 5x4 \frac{5x}{4} and the second number as 3x2\frac{3x}{2}​.
    The ratio of the first number to the second number is:
    5x43x2=5x4×23x=56\frac{\frac{5x}{4}}{\frac{3x}{2}} = \frac{5x}{4} \times \frac{2}{3x} = \frac{5}{6}​​

    Answer: The ratio between the first and second numbers is 5:6.

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