Correct option is Bi=141.4sin(314t)i=Imsin(ωt)Im2=141.41.414Irms=100 Aω=2πff=ω2π=3142×3.14f=50 Hzi = 141.4 \sin (314t) \\i = I_m \sin (\omega t) \\\frac{I_m}{\sqrt{2}} = \frac{141.4}{1.414} \\I_{\text{rms}} = 100 \text{ A} \\\omega = 2\pi f \\f = \frac{\omega}{2\pi} = \frac{314}{2 \times 3.14} \\f = 50 \text{ Hz}i=141.4sin(314t)i=Imsin(ωt)2Im=1.414141.4Irms=100 Aω=2πff=2πω=2×3.14314f=50 Hz