If the distance between A and B is 1084 Km. From A, Vishal goes to B with speed 104 km/h and return to A with the speed 112 km/h. Find the average speed of Vishal. (rounded off to two decimal place)

Correct option is C

Given:

The distance between A and B is 1084 km. Vishal goes from A to B with a speed of 104 km/h and returns to A with a speed of 112 km/h.

Formula Used:

Average speed =$$\frac{2 \times \text{Speed 1} \times \text{Speed 2}}{\text{Speed 1} + \text{Speed 2}}$$​​

Solution:

The distance between A and B is 1084 km.

The speed from A to B is 104 km/h, and the speed from B to A is 112 km/h.

Average speed =$$\frac{2 \times 104 \times 112}{104 + 112} = \frac{2 \times 11648}{216} = \frac{23296}{216} \approx 107.85$$​​

So, the average speed of Vishal is approximately 107.85 km/h.