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    If the difference between the exterior and the interior angles of a regular polygon is 60°, with an interior angle being greater than the correspondin
    Question

    If the difference between the exterior and the interior angles of a regular polygon is 60°, with an interior angle being greater than the corresponding exterior angle, then find the number of sides of the polygon.

    A.

    6

    B.

    5

    C.

    8

    D.

    7

    Correct option is A

    Given:

    Difference between interior and exterior angles = 60 60^\circ​​
    Interior angle > Exterior angle

    Formula Used:
    For a regular polygon with n sides:

    Interior angle = (n2)×180n\frac{(n - 2) \times 180^\circ}{n}​​

    Exterior angle =360n \frac{360^\circ}{n}​​
    Difference = Interior angle – Exterior angle

    Solution:

    ((n2)×180n)(360n)=60 180n360360n=60 180n720n=60\left( \frac{(n - 2) \times 180}{n} \right) - \left( \frac{360}{n} \right) = 60 \\ \ \\\frac{180n - 360 - 360}{n} = 60\\ \ \\\frac{180n - 720}{n} = 60

    180n  - 720 = 60n

    120n = 720

    n = 6 sides

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