For a regular polygon, the sum of the interior angles is 300% more than the sum of its exterior angles. Each interior angle of the polygon measures x°. What is the value of x?​

Correct option is D

Given:

The sum of interior angles is 300% more than the sum of exterior angles.

Each interior angle = $$x^\circ$$​​

Formula Used:

Sum of exterior angles of any polygon = $$360^\circ$$​​

Sum of interior angles = 180(n - 2), where n = number of sides 

Each interior angle = $$\frac{180(n - 2)}{n}$$​
Solution:

If the interior sum is 300% more than exterior sum: 

Interior Sum = 360 + 300% of 360 = 360 + 1080 = 1440^∘

180(n - 2) = 1440

n = $$\frac{1440}{180}$$​ + 2 = 8 + 2 = 10

Now,

Each interior angle = $$\frac{180(10 - 2)}{10} = \frac{180 \times 8}{10} = \frac{1440}{10} = 144^\circ$$​​