If the diagonals of a rhombus are 48 cm and 64 cm, then what is the perimeter of the rhombus?

Correct option is D

Given:
Diagonal 1 = 48 cm
Diagonal 2 = 64 cm
Formula Used:
Side of rhombus $$s = \sqrt{(\frac {d1}{2}^2) + (\frac {d2}{2}^2)}$$​​
Perimeter of rhombus = 4 × side
Solution:
​$$s =\sqrt{(48/2)^2 + (64/2)^2)}\\s = \sqrt{24^2 + 32^2}\\s =\sqrt{576 + 1024)}= \sqrt{1600} = 40 cm$$​​
Perimeter = 4 × 40 = 160 cm