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If tan A = 67\frac6776​​. find the value of 7sin⁡A+2cos⁡A7sin⁡A−2cos⁡A\frac{7\sin A + 2\cos A}{7\sin A - 2\cos A}7sinA−2cosA7sinA+2cosA​​
Question

If tan A = 67\frac67​. find the value of 7sinA+2cosA7sinA2cosA\frac{7\sin A + 2\cos A}{7\sin A - 2\cos A}

A.

9/5

B.

-19/5

C.

2

D.

5

Correct option is C

Given:
tanA=67\tan A = \frac{6}{7}​​
Expression to evaluate = 7sinA+2cosA7sinA2cosA\frac{7\sin A + 2\cos A}{7\sin A - 2\cos A}​​
Formula Used:
tanA=sinAcosA\tan A = \frac{\sin A}{\cos A}​​
Solution:
Divide the numerator and the denominator of the expression by \cos A.
7sinAcosA+2cosAcosA7sinAcosA2cosAcosA\frac{\frac{7\sin A}{\cos A} + \frac{2\cos A}{\cos A}}{\frac{7\sin A}{\cos A} - \frac{2\cos A}{\cos A}}​​
Simplify using tanA.\tan A.​​
7tanA+27tanA2 \frac{7\tan A + 2}{7\tan A - 2}​​
Substitute the value of tan A.
=7×67+27×672= \frac{7 × \frac{6}{7} + 2}{7 × \frac{6}{7} - 2}​​

=6+262= \frac{6 + 2}{6 - 2}​​
=84= \frac{8}{4}​​
= 2
Final Answer
So the correct answer is (c)

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