If recommended dose of fertilizer for finger millet is 40:30:20 kg N:P:K per hectare, then what amount of fertilizer is required for one acre area, If the source is urea, DAP, and MoP, respectively.

Correct option is B

Given: Dose = 40:30:20 kg N:P₂O₅:K₂O per hectare. Sources: Urea (46% N), DAP (18% N, 46% P₂O₅), MoP (60% K₂O). 1 ha ≈ 2.5 acres.

Formula:
Per-acre nutrient need = (Per-ha dose) ÷ 2.5
Fertilizer required = (Nutrient required) ÷ (Nutrient fraction in fertilizer)

Solution:
Per-acre nutrient requirement:
N = 40/2.5 = 16 kg; P₂O₅ = 30/2.5 = 12 kg; K₂O = 20/2.5 = 8 kg.

1. DAP for P₂O₅:
   DAP needed = 12 ÷ 0.46 = 26.09 ≈ 26 kg/acre.
   N supplied by this DAP = 26 × 0.18 = 4.68 ≈ 4.7 kg N.
2. Remaining N from Urea:
   Remaining N = 16 − 4.7 = 11.3 kg.
   Urea needed = 11.3 ÷ 0.46 = 24.57 ≈ 24.5 kg/acre.
3. MoP for K₂O:
   MoP needed = 8 ÷ 0.60 = 13.33 ≈ 13 kg/acre.

Hence, Urea:DAP:MoP ≈ 24.5 : 26 : 13 => option (b).