If p and q are the roots of$$x^2 + 4x - 21 = 0$$ and p < q . then the quadratic equation in x whose roots are (p - 1) and [q + 1) is?

Correct option is C

Given:

x^2​+4x-21 = 0, 

Solution: 

​$$x^2 +4x-21=0 \\ \ \\ x^2+7x-3x-21 =0 \\ \ \\ x(x+7)-3(x+7) = 0 \\ \ \\ (x-3)(x+7) =0 \\ \ \\ x = 3, -7$$​​

then, p + 1 = 3 + 1 = 4 

q - 1 = -7 - 1 = -8

So, 

​$$(x-4)(x+8) \\ \ \\ =x^2+8x-4x-32 \\ \ \\ = x^2 +4x-32$$​​