If length and breadth of a rectangle are increased and decreased by 10 percent respectively, then what is the percentage change in the area of rectangle?

Correct option is B

Given:
Increment in length = 10%
decrement in breadth = 10%
Formula Used:
Percentage change = (A + B + $$\frac{AB}{100}$$​)%
Where A and B are successive percentage changes
Solution:
A = 10% and B = -10%
Percentage change = [10 - 10 + $$\frac{10(-10)}{100}$$​]%
Percentage change = -1%
Alternate Solution:
Let the original length and breadth of the rectangle be L and B, respectively.
The new length will be increased by 10%, so the new length will be L × 1.10.
The new breadth will be decreased by 10%, so the new breadth will be B × 0.90.
The new area of the rectangle will be:
New Area = (L × 1.10) × (B × 0.90) = L × B × 1.10 × 0.90
New Area = L × B × 0.99
Now, the percentage change in the area will be:
Percentage Change in Area = (1.10 × 0.90 - 1) × 100 = 0.99 - 1 = -0.01
Percentage Change in Area = -1%