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if '-' is interchanged with '÷\div÷' and '3' is interchanged with '6', then which of the following equation will be correct?​
Question

if '-' is interchanged with '÷\div' and '3' is interchanged with '6', then which of the following equation will be correct?​

A.

4+6÷33×2=84 + 6 \div 3 - 3 \times 2 = 8​​

B.

4+6÷33×2=104 + 6 \div 3 - 3 \times 2 = 10​​

C.

4+6÷33×2=54 + 6 \div 3 - 3 \times 2 = 5​​

D.

4+6÷33×2=124 + 6 \div 3 - 3 \times 2 = 12​​

Correct option is C

Give equation is:
4+6÷33×24 + 6 \div 3 - 3 \times 2

‘-’ and ‘÷’ are interchanged and also ‘3’ and ‘6’ are interchanged. 

Logic: interchange mathematical operators and solve as per BODMAS rule.
Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}​​

Replacing symbols and numbers in the given equation we get:

4+36÷6×24+31×272=54 + 3 - 6 \div 6 \times 2 \\4 + 3 - 1 \times 2\\7-2=5

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