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    if '-' is interchanged with '÷\div÷' and '3' is interchanged with '6', then which of the following equation will be correct?​
    Question

    if '-' is interchanged with '÷\div' and '3' is interchanged with '6', then which of the following equation will be correct?​

    A.

    4+6÷33×2=84 + 6 \div 3 - 3 \times 2 = 8​​

    B.

    4+6÷33×2=104 + 6 \div 3 - 3 \times 2 = 10​​

    C.

    4+6÷33×2=54 + 6 \div 3 - 3 \times 2 = 5​​

    D.

    4+6÷33×2=124 + 6 \div 3 - 3 \times 2 = 12​​

    Correct option is C

    Give equation is:
    4+6÷33×24 + 6 \div 3 - 3 \times 2

    ‘-’ and ‘÷’ are interchanged and also ‘3’ and ‘6’ are interchanged. 

    Logic: interchange mathematical operators and solve as per BODMAS rule.
    Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}​​

    Replacing symbols and numbers in the given equation we get:

    4+36÷6×24+31×272=54 + 3 - 6 \div 6 \times 2 \\4 + 3 - 1 \times 2\\7-2=5

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