If in a code language, If ‘A’ stands for ‘÷’, ‘B’ stands for ‘×’, ‘C’ stands for ‘+’ and ‘D’ stands for ‘−’, then the resultant of which of the following would be 55?

Decoding: 16−112÷63+77×31

=$$16 - \frac{112}{63} + 77 \times 31$$

=$$16 - \frac{16}{9} + {77} \times {31}$$​​

=16 - 1.777 + 2387

=2401.22

Result : $$2401.22 \neq 55.$$​​

Decoding: 16÷112×63+77−31

=$$\frac{16}{112}\times63+77-31$$​​

=9 + 77 – 31

=55

Result: 55 = 55.

Decoding: 16×112+63÷77−31

=$$16\times112+\frac{63}{77}-31$$​​

=1792 + 0.8181 – 31

=1761.8181

Result : $$1761.8181 \neq 55.$$​​

Decoding: 16+112−63÷77×31

=$$16 + 112 – \frac{63}{77}\times31$$​​

=16 +112 – 25.36

=102.64 

Result:$$102.64 \neq 55.$$​​

The correct option is (b): 16 A 112 B 63 C 77 D 31 = 50 .