If f(x) = $$\frac{x + 3}{x - 1}$$, find the value of f(f(f(2))).​

Correct option is D

Given:

$$f(x) = \frac{x + 3}{x - 1}$$ 

find the value of f(f(f(2)))

Solution:

​$$f(x) = \frac{x + 3}{x - 1}$$ 

For f(2) We substitute x = 2 into the function f(x):

​$$f(2) = \frac{2 + 3}{2 - 1} = \frac{5}{1} = 5$$ 

For f(f(2)), which is f(5)

Now, we need to find $f(5)$. We substitute $x=5$ into the function $f(x)$:

$$f(5) = \frac{5 + 3}{5 - 1} = \frac{8}{4} = 2$$ 

For f(f(f(2))), which is f(2)  

​$$f(2) = 5$$

Thus $$f(f(f(2))) = 5$$​​​