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If each interior angle of a regular polygon measures 108°, that polygon has _________ sides.
Question

If each interior angle of a regular polygon measures 108°, that polygon has _________ sides.

A.

6

B.

5

C.

4

D.

10

Correct option is B

Given:

each interior angle=  108°

Concept Used:

Interior Angle=(n2)×180n\text{Interior Angle} = \frac{(n-2) \times 180^\circ}{n} 

​where n is the number of sides.

Solution:

Given that the interior angle is 108°,  substitute it in formula:

108=(n2)×180n108 = \frac{(n-2) \times 180}{n} 

108n=(n2)×180108n = (n-2) \times 180​​

108n=180n360108n = 180n - 360 

180n108n=360180n - 108n = 360 

72n=36072n = 360 

n=36072=5n = \frac{360}{72} = 5 

Thus, the polygon has 5 sides.

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