Correct option is A
Given:
cosθ=cosα
Solution:
θ=α+2nπ comes from the cosine function being positive in the first and fourth quadrants.
θ=−α+2nπ comes from the cosine function being positive in the second and third quadrants.
Thus, the general solution is:
θ=α+2nπorθ=−α+2nπwheren∈Z.
Thus, option (a) is right.