arrow
arrow
arrow
If cos θ = cos α then general solution for θ is:
Question

If cos θ = cos α then general solution for θ is:

A.

θ = 2nπ ± α, nϵZ

B.

θ = 32\frac{3\text {nπ}}{2}​ ± α, nϵZ

C.

θ = nπ ± α, nϵZ

D.

θ = 2\frac{\text{nπ}}{2}​ + α, nϵZ

Correct option is A

Given:

cosθ=cosα\cos \theta = \cos \alpha

Solution:

θ=α+2nπ\theta = \alpha + 2n\pi​ comes from the cosine function being positive in the first and fourth quadrants.

θ=α+2nπ\theta = -\alpha + 2n\pi​ comes from the cosine function being positive in the second and third quadrants.

Thus, the general solution is:

θ=α+2nπorθ=α+2nπwhere nZ.\theta = \alpha + 2n\pi \quad \text{or} \quad \theta = -\alpha + 2n\pi \quad \text{where} \, n \in \mathbb{Z}.

Thus, option (a) is right.

Free Tests

Free
Must Attempt

CBT-1 Full Mock Test 1

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon100 Marks
  • timerIcon90 Mins
languageIcon English
Free
Must Attempt

RRB NTPC Graduate Level PYP (Held on 5 Jun 2025 S1)

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon100 Marks
  • timerIcon90 Mins
languageIcon English
Free
Must Attempt

CBT-1 General Awareness Section Test 1

languageIcon English
  • pdpQsnIcon40 Questions
  • pdpsheetsIcon30 Marks
  • timerIcon25 Mins
languageIcon English
test-prime-package

Access ‘RRB NTPC’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
354k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow