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If △ABC is an isosceles triangle such that ∠ABC = 90°, then the true statement about △ABC is-
Question

If △ABC is an isosceles triangle such that ∠ABC = 90°, then the true statement about △ABC is-

A.

2(AC)2=(AB)22(AC)^2 = (AB)^2 \\​​

B.

(AB)2+(AC)2=(BC)2(AB)^2 + (AC)^2 = (BC)^2 \\​​

C.

(BC)2+(AC)2=(AB)2(BC)^2 + (AC)^2 = (AB)^2 \\​​

D.

(AC)2=2(AB)2(AC)^2 = 2(AB)^2 \\​​

Correct option is D

Given:
∆ABC is an isosceles triangle with ∠ABC = 90°
Concept used:
·       Right-angled triangle with a 90° angle at B.
·       Since it’s isosceles, sides AB = BC.
·       Use Pythagoras Theorem: In right-angled triangle, (Hypotenuse)² = (Base)² + (Height)²
Formula used:
In ∆ABC,
If AB = BC and ∠ABC = 90°,
Then AC² = AB² + BC² = 2(AB)²
Solution:
Since AB = BC and angle B = 90°,
=> AC² = AB² + BC²
=> AC² = AB² + AB² = 2(AB)²
Correct answer is (d) (AC)² = 2(AB)².

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