A triangle has angles $$A=50^∘,B=60^∘$$​, and side AB=10 cm. Find the third angle ?

Correct option is C

Given
Angle A = $$50^\circ$$​​
Angle B = $$60^\circ$$​​
Side AB = 10 cm

Formula Used
Sum of angles in a triangle = $$180^\circ$$​​

Solution
The vertices of the triangle are A, B, and C.
​$$Angle \ C = 180^\circ - (\text{Angle A} + \text{Angle B}) \\Angle \ C = 180^\circ - (50^\circ + 60^\circ)\\Angle\ C = 180^\circ - 110^\circ = 70^\circ$$​​
Thus, the third angle is Angle C = $$70^0$$​​

Final Answer
So the correct answer is (c)