If a wire of length 10 m having cross section area of 1m² and a resistance of 5 ohms the specific resistance of the material is:

Correct option is A

​$$\text{The specific resistance (resistivity) of a material is calculated using:} \\\\\rho = \frac{R \cdot A}{L} \\\\\text{Where:} \\\rho \text{ = Resistivity (ohm-meter)} \\R \text{ = Resistance (ohms)} \\A \text{ = Cross-sectional area (m}^2\text{)} \\L \text{ = Length (m)} \\\\\text{Given:} \\R = 5\ \Omega, \\A = 1\ \text{m}^2, \\L = 10\ \text{m} \\\\\text{Substituting the values:} \\\rho = \frac{5\ \Omega \cdot 1\ \text{m}^2}{10\ \text{m}} \\\\\rho = \frac{5}{10}\ \Omega\text{-meter} \\\\\rho = 0.5\ \Omega\text{-meter}$$​​

Therefore, the specific resistance of the material is 0.5 ohm-meter.
The correct answer is (a) 0.5 ohm-meter.