If a solid sphere of radius 10 cm is melted into 8 spherical solid balls of equal radius, then what will be the surface area of each such ball? [Use π=$$\frac{22}7$$​]

Correct option is B

Given:

Radius of the original solid sphere (R) = 10 cm

Number of smaller spherical balls = 8

Formula Used:

Surface Area of the sphere = 4πr² 

Solution:  

Let the radius of the smaller sphere r 

Total volume of the original sphere is equal to the combined volume of the smaller balls. 

Volume equality: R³= 8r³​

10³ = 8r³ 

1000 = 8r³ 

r³ = 125 

r = 5 

Now,  

Surface area of each ball ;

= 4$$\times\frac{22}7\times5^2$$ 

= $$4\times\frac{22}7\times25$$ 

= $$\frac{22}7\times100$$ 

= $$\frac{2200}7$$  =  $$314\frac27$$cm²​