If A's salary is 12% more than that of B, then by what percentage is B's salary less than that of A (correct to two decimal places)?​

Correct option is B

Given:

A's salary is 12% more than B's salary.

Solution: 

Let B's salary be ₹100

Then A's salary = ₹112

Difference = 112 - 100 = 12

Percentage less = $$\frac{12}{112} \times 100 \approx 10.71\%$$​​

Thus, B's salary is 10.71% less than A's salary