If a man’s age is four times the sum of the ages of his three children, and after 6 years his age will be twice the sum of the
ages of his three children, then what is the man’s present age?

Correct option is C

Given:

Man’s present age = 4 × (sum of present ages of his three children)

After 6 years: Man’s age = 2 × (sum of children's ages after 6 years)

Solution:

Let sum of children's present ages = x

Man’s present age = 4x

After 6 years:

Man’s age = 4x + 6

Children's total age = x + 3 × 6 = x + 18

Thus,

4x + 6 = 2(x + 18)

4x - 2x = 36 - 6

2x = 30

x = 15

Man’s present age = 4x = 4 × 15 = 60 years.

Thus, the man's present age is 60 years.