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If a/3=b/4=c/7, then (a+b+c)/c is equal to:
Question

If a/3=b/4=c/7, then (a+b+c)/c is equal to:

A.

4

B.

1

C.

3

D.

2

Correct option is D

Given:
a/3 = b/4 = c/7 = k (let this common ratio be k), so a = 3k, b = 4k, and c = 7k.
Solution:
Now, substitute these values into (a + b + c)/c:
(a + b + c)/c = (3k + 4k + 7k)/7k = 14k/7k = 2
Thus, (a + b + c)/c equals 2.

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