Given:
a/3 = b/4 = c/7 = k (let this common ratio be k), so a = 3k, b = 4k, and c = 7k.
Solution:
Now, substitute these values into (a + b + c)/c:
(a + b + c)/c = (3k + 4k + 7k)/7k = 14k/7k = 2
Thus, (a + b + c)/c equals 2.
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90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishThe sum of squares of all the roots of the equation:
is:
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The value of is
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