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If (√5-1)/(√5+1)-(√5+1)/(√5-1) = a + b√5, then the value of (a + b) (a - b) ÷ a² + b² is:
Question

If (√5-1)/(√5+1)-(√5+1)/(√5-1) = a + b√5, then the value of (a + b) (a - b) ÷ a² + b² is:

A.

-2

B.

0

C.

-1

D.

3

Correct option is C

Solution:

515+15+151\frac{\sqrt{5} - 1}{\sqrt{5} + 1} - \frac{\sqrt{5} + 1}{\sqrt{5} - 1}  =a +b5\sqrt5

(51)(51)(5+1)(51)(5+1)(5+1)(5+1)(51) \frac{(\sqrt{5} - 1)(\sqrt{5} - 1)}{(\sqrt{5} + 1)(\sqrt{5} - 1)} - \frac{(\sqrt{5} +1)(\sqrt{5} +1)}{(\sqrt{5} + 1)(\sqrt{5} - 1)} =a +b5\sqrt5​​

6254\frac{6-2\sqrt5}{4} -6+254\frac{6+2\sqrt5}{4}=a +b5\sqrt5 

o -5\sqrt5 =a +b5\sqrt5

a=0 , b=-1 

so, value 

(a + b) (a - b) ÷ a² + b² 

put a=0 , b=-1 

(0 + (-1)) (0 - (-1)) ÷ (0)² + (-1)²

=  (-1)(1)

=-1 

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