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    If 3x2y=4872\frac{3x}{2y}=\frac{48}{72}2y3x​=7248​​ then xy\frac{x}{y}yx​​ then in its lowest term is:
    Question

    If 3x2y=4872\frac{3x}{2y}=\frac{48}{72}​ then xy\frac{x}{y}​ then in its lowest term is:

    A.

    49\frac{4}{9}​​

    B.

    59\frac{5}{9}​​

    C.

    39\frac{3}{9}​​

    D.

    29\frac{2}{9}​​

    Correct option is A

    Given:

    3x2y=4872\frac{3x}{2y} = \frac{48}{72}

    Required: Find xy \frac{x}{y}​ in its lowest terms.

    Solution:

    3x2y=4872=48÷2472÷24=23\frac{3x}{2y} =\frac{48}{72} = \frac{48 \div 24}{72 \div 24} = \frac{2}{3}​​

    3x×3=2y×23x \times 3 = 2y \times 2

    9x = 4y

    xy=49\frac{x}{y} = \frac{4}{9}

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