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If 3x2y=4872\frac{3x}{2y}=\frac{48}{72}2y3x​=7248​​ then xy\frac{x}{y}yx​​ then in its lowest term is:
Question

If 3x2y=4872\frac{3x}{2y}=\frac{48}{72}​ then xy\frac{x}{y}​ then in its lowest term is:

A.

49\frac{4}{9}​​

B.

59\frac{5}{9}​​

C.

39\frac{3}{9}​​

D.

29\frac{2}{9}​​

Correct option is A

Given:

3x2y=4872\frac{3x}{2y} = \frac{48}{72}

Required: Find xy \frac{x}{y}​ in its lowest terms.

Solution:

3x2y=4872=48÷2472÷24=23\frac{3x}{2y} =\frac{48}{72} = \frac{48 \div 24}{72 \div 24} = \frac{2}{3}​​

3x×3=2y×23x \times 3 = 2y \times 2

9x = 4y

xy=49\frac{x}{y} = \frac{4}{9}

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