If $$2^x × 4^{12} × 8^3 = 16^{11}$$​ then the value of x is:

Given: 

 $$2^x × 4^{12} × 8^3 = 16^{11}$$  

Formula Used: 

​$${a}^n \times a^m= {a}^{n+m}$$ 

Solution: 

​$$2^x × 4^{12} × 8^3 = 16^{11} \\ \ \\ 2^x\times (2^2)^{12} \times (2^3)^3 = (2^4)^{11}\\ \ \\ 2^{x+24+9} = 2^{44}$$ 

Now, comparing the powers ,

x + 24 + 9 = 44 

x  + 33 = 44 

x = 44 - 33 

x = 11  

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