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    If 29×2×742÷2809=y+78429 \times 2 \times 742 \div \sqrt{2809} = y + 78429×2×742÷2809​=y+784, then find the value of y.​
    Question

    If 29×2×742÷2809=y+78429 \times 2 \times 742 \div \sqrt{2809} = y + 784, then find the value of y.​

    A.

    35

    B.

    36

    C.

    28

    D.

    26

    Correct option is C

    Given:

    29×2×742÷2809=y+78429 \times 2 \times 742 \div \sqrt{2809} = y + 784

    Concept Used:

    Operation preference wiseSymbolBrackets[],,()Orders, ofx(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & ^x(power), √ (root) , of \\ \hline \text{Division}& ÷ \\\hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline\end{array}

    Solution:

    29×2×742÷2809=y+78429 \times 2 \times 742 \div \sqrt{2809} = y + 784

    ​​29×2×742÷53=y+78429 \times 2 \times 742 \div53= y + 784

    29×2×14=y+78429 \times 2 \times 14 = y + 784

    812 = y + 784

    y = 812 - 784 =28 

    Option (C) is right.


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