​$$\text{If } {\sqrt{1+\frac{x}{121}}=\frac{12}{11}}, \text{ then the value of } x \text{ is:}$$​​​

Correct option is A

Given:

​$$\sqrt{1+\frac{x}{121}}$$= $$\frac{12}{11}$$   

Solution:

​$$\sqrt{1+\frac{x}{121}}$$ = $$\frac{12}{11}$$ 

We do both side squire 

​$$\left (\sqrt{1+\frac{x}{121}}\right)^2$$ = $$\left(\frac{12}{11}\right)^2$$ 

1+$$\frac{x}{121}$$ = $$\frac{144}{121}$$ 

$$\frac{121+x}{121}$$ = $$\frac{144}{121}$$ 

121+x = 144

x = 144-121

X= 23

Option (a)