Identify the value of the power factor of a parallel resonant circuit at resonance.

Correct option is B

The power factor of a circuit is defined as:

$$\text{Power Factor (PF)} = \cos \phi = \frac{\text{Real Power} (P)}{\text{Apparent Power} (S)}$$​

In a parallel resonant circuit at resonance:
The inductive reactance (XL) and capacitive reactance (XC) cancel each other, resulting in the circuit behaving as a purely resistive circuit.
In a resistive circuit, the phase angle (ϕ) between the voltage and current is , making the power factor:
PF=cos0∘=1