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Identify the double displacement reaction from the following.
Question

Identify the double displacement reaction from the following.

A.

Fe(s)+CuSO_4 (aq)→FeSO_4 (aq)+Cu(s)

B.

Pb(s)+CuCl_2 " (aq) "→PbCl_2 " (aq) "+Cu(s)

C.

Zn(s)+CuSO_4 " (aq) "→ZnSO_4 " (aq) "+Cu(s)

D.

Na_2 SO_4 " (aq) "+BaCl_2 " (aq) "→BaSO_4 " (s) "+2NaCl(aq)

Correct option is D

​​​The correct answer is option (d)Na2SO4(aq)+BaCl2(aq)BaSO4(s)+2NaCl(aq)Na_2 SO_4 (aq) +BaCl_2 (aq) →BaSO_4 (s) +2NaCl(aq)   =   Double displacement reaction.

Information Booster :

 Double displacement reaction : In a double displacement reaction , two compounds exchange their ions to form two new compounds.

The general form is:

AB+CD→AD+CBAB + CD \rightarrow AD + CB                             AB+CDAD+CB

Option (d) :Na2SO4(aq)+BaCl2(aq)BaSO4(s)+2NaCl(aq)

In this reactionNa2SO4Na_2SO_4​ and BaCl2BaCl_2​exchange ions:.

  • Na+Na^+ from Na2SO4Na_2SO_4 pair with ClCl^- to form NaCl
  • Ba2+\text{Ba}^{2+} from BaCl2BaCl_2 pair with SO42S O_4^{2-} to form BaSO4Ba SO_4    

This is a double displacement reaction.

This reaction involves the exchange of ions between two compounds and results in the formation of an insoluble precipitate BaSO₄\text{BaSO₄}BaSO4BaSO_4​ making it a double displacement reaction.​

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