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    Identify the double displacement reaction from the following.
    Question

    Identify the double displacement reaction from the following.

    A.

    Fe(s)+CuSO_4 (aq)→FeSO_4 (aq)+Cu(s)

    B.

    Pb(s)+CuCl_2 " (aq) "→PbCl_2 " (aq) "+Cu(s)

    C.

    Zn(s)+CuSO_4 " (aq) "→ZnSO_4 " (aq) "+Cu(s)

    D.

    Na_2 SO_4 " (aq) "+BaCl_2 " (aq) "→BaSO_4 " (s) "+2NaCl(aq)

    Correct option is D

    ​​​The correct answer is option (d)Na2SO4(aq)+BaCl2(aq)BaSO4(s)+2NaCl(aq)Na_2 SO_4 (aq) +BaCl_2 (aq) →BaSO_4 (s) +2NaCl(aq)   =   Double displacement reaction.

    Information Booster :

     Double displacement reaction : In a double displacement reaction , two compounds exchange their ions to form two new compounds.

    The general form is:

    AB+CD→AD+CBAB + CD \rightarrow AD + CB                             AB+CDAD+CB

    Option (d) :Na2SO4(aq)+BaCl2(aq)BaSO4(s)+2NaCl(aq)

    In this reactionNa2SO4Na_2SO_4​ and BaCl2BaCl_2​exchange ions:.

    • Na+Na^+ from Na2SO4Na_2SO_4 pair with ClCl^- to form NaCl
    • Ba2+\text{Ba}^{2+} from BaCl2BaCl_2 pair with SO42S O_4^{2-} to form BaSO4Ba SO_4    

    This is a double displacement reaction.

    This reaction involves the exchange of ions between two compounds and results in the formation of an insoluble precipitate BaSO₄\text{BaSO₄}BaSO4BaSO_4​ making it a double displacement reaction.​

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