How many moles are present in 54 g of He?

Correct option is B

The correct answer is (b) 13.5 moles

Explanation:

·       The formula to calculate moles is:

·       Moles= Given mass / Molar mass

·       Molar mass of Helium (He) = 4 g/mol.

·       Given mass = 54 g.

·       Moles = 54 ÷ 4 = 13.5.

·       Therefore, 54 g of helium contains 13.5 moles.

Information Booster:

·       1 mole of any substance contains Avogadro’s number of particles (6.022 × 10²³ atoms or molecules).

·       Helium being a noble gas exists as monoatomic atoms, so 1 mole = 6.022 × 10²³ atoms of He.