Four dice are thrown simultaneously. The number of ways in which we get the total sum 23 on all dices is:

Correct option is C

Given:

Four dice are thrown simultaneously.

Total sum required on dices = 23

Solution:

Total sum of 23 on four dices can be achieved by,

(6,6,6,5) – 4!/3!

= $$= \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1}$$​

= 4 ways