​For a regular polygon. the sum of the interior angles is 200% more than the sum of its exterior angles. Each interior angle of the polygon measures x°. What is the value of x°?

Correct option is B

​Given:
Sum of interior angles is 200% more than sum of exterior angles.

Formula Used:

Sum of exterior angles = 360^∘

Sum of interior angles = $$(n - 2) \times 180^\circ$$​​

Solution:

​$$\text{Sum of interior angles} = 3 \times \text{Sum of exterior angles}\\ \ \\ = 3 \times 360 = 1080^\circ$$​

Now, 

​$$(n - 2) \times 180 = 1080 \\ \ \\ n - 2 = 6 \\ \ \\ n = 8$$​​

Each interior angle:

​$$\frac{(n - 2) \times 180}{n} = \frac{6 \times 180}{8} = 135^\circ$$​​